0=10y^2-9y+2

Solution for 0=10y^2-9y+2 equation:

0=10y^2-9y+2

We move all terms to the left:

0-(10y^2-9y+2)=0

We add all the numbers together, and all the variables

-(10y^2-9y+2)=0

We get rid of parentheses

-10y^2+9y-2=0

a = -10; b = 9; c = -2;
Δ = b2-4ac
Δ = 92-4·(-10)·(-2)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-1}{2*-10}=\frac{-10}{-20}
=1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+1}{2*-10}=\frac{-8}{-20}
=2/5
$